64+4x^2+(1/64)x^4

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Solution for 64+4x^2+(1/64)x^4 equation: 


x in (-oo:+oo)

(1/64)*x^4+4*x^2+64 = 0

1/64*x^4+4*x^2+64 = 0

t_1 = x^2

1/64*t_1^2+4*t_1^1+64 = 0

1/64*t_1^2+4*t_1+64 = 0

DELTA = 4^2-(1/64*4*64)

DELTA = 12

DELTA > 0

t_1 = (12^(1/2)-4)/(1/64*2) or t_1 = (-12^(1/2)-4)/(1/64*2)

t_1 = 32*(2*3^(1/2)-4) or t_1 = 32*(-2*3^(1/2)-4)

t_1 = 32*(-2*3^(1/2)-4)

x^2-(32*(-2*3^(1/2)-4)) = 0

x^2-32*(-2*3^(1/2)-4) = 0

1*x^2 = -(-32*(-2*3^(1/2)-4)) // : 1

x^2 = 32*(-2*3^(1/2)-4)

t_1 = 32*(2*3^(1/2)-4)

x^2-(32*(2*3^(1/2)-4)) = 0

x^2-32*(2*3^(1/2)-4) = 0

1*x^2 = -(-32*(2*3^(1/2)-4)) // : 1

x^2 = 32*(2*3^(1/2)-4)

x belongs to the empty set

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